Lab 1: post-lab assignment - Population Genetics By Amina Nur and Timothea Muljadi
Part 1: Distribution of Genes in a Population
Ho: The distribution of genes in the bean population does not differ from the Mendelian ratios.
Ha: The distribution of genes in the bean population differ from the Mendelian ratios.
Prediction:
If the distribution of genes in a population does not differ from the Mendelian ratios, then out of 50 pairs of beans, the genotype distribution will be: 25% (12.5: 12/13 pairs) homozygous white (white/white), 25% (12.5: 13/12 pairs) homozygous speckled (speckled/speckled), and 50% (25 pairs) heterozygous (white/speckled).
Figure 1. Observed frequencies of the genotypes in the bean population compared to the Mendelian ratios.
Figure 2. Photo of the observed bean pairings from the gene pool.
Table 1. Chi-squared calculations for observed and expected distribution of genes in a population:
Observed (O)
|
Expected (E)
|
O-E
|
(O-E)2
|
(O-E)2/E
| |
Homozygous White
|
13
|
12.5
|
0.5
|
0.25
|
0.02
|
Homozygous Speckled
|
13
|
12.5
|
0.5
|
0.25
|
0.02
|
Heterozygous
|
24
|
25
|
-1
|
1
|
0.04
|
Total
|
50
|
50
|
0.08
|
Table 1. shows that chi-square =0.08 which is smaller than the critical value (5.99 )
Degrees of Freedom = 4-1 = 3 (critical value = 5.99)
Based on the results, the data does not support the hypothesis because the distribution of genes in the bean population follows the Mendelian ratios. The expected values are based on the Mendelian ratios calculated using the Punnett square, where out of 50 pairs of beans there will be 25% (12.5: 12/13 pairs) homozygous white (white/white), 25% (12.5: 12/13 pairs) homozygous speckled (speckled/speckled), and 50% (25 pairs) heterozygous (white/speckled). Figure 1 shows that the observed values are slightly different than the expected value. However, based on table 1, the chi-square is less than the critical value for degrees of freedom of 2 (0.08<5.99), meaning there is not a significant deviation from the expected genotype ratios. Therefore, we cannot reject the null hypothesis that the distribution of genes in the bean population follows the Mendelian ratios.
Part 2: Genetic Drift or Natural Selection
Ho: The allele frequencies of the bean population do not change over generations.
Ha: The allele frequencies of the bean population change over generations.
Prediction:
If the allele frequencies of the bean population change over generations, then the allele frequencies in the 10th generation will be the same as the 1st generation.
Figure 3. The number of allele frequency of four different types of beans after random selection over generations for population A (50 beans/ trail).
Figure 4. The number of allele frequency of four different types of beans after random selection over generations for population B (50 beans/ trail).
Table 2. Chi-squared calculations for observed and expected generations in population A.
Observed (O)
|
Expected(E)
|
O-E
|
(O-E)2
|
(O-E)2/E
| |
Red
|
21
|
13
|
8
|
64
|
4.92
|
Speckled
|
27
|
17
|
10
|
100
|
5.88
|
Black
|
2
|
11
|
-9
|
81
|
7.36
|
White
|
0
|
9
|
-9
|
81
|
9
|
Total
|
50
|
50
|
27.16
|
Table 2.shows that chi-square =27.16 which is bigger than the critical value (7.82 )
Degrees of Freedom = 4-1 = 3 (critical value = 7.82)
Figure 1. First and tenth generation in population A:
First Generation for population A: Expected Tenth Generation for population A: Observed
Figure 5. Photo of the expected (first generation) and observed (tenth generation) of a populations of four different types of beans from population A. It demonstrates the sizes of beans in each allele.
Table 3. Chi-squared calculations for observed and expected generations in population B.
Observed (O)
|
Expected(E)
|
O-E
|
(O-E)2
|
(O-E)2/E
| |
Red
|
12
|
12
|
0
|
0
|
0
|
Speckled
|
38
|
8
|
30
|
900
|
112.5
|
Black
|
0
|
14
|
-14
|
196
|
14
|
White
|
0
|
16
|
-16
|
256
|
16
|
Total
|
50
|
50
|
142.5
|
Table 3. shows that chi-square =142.5 which is bigger than the critical value (7.82 )
Degrees of Freedom = 4-1 = 3 (critical value = 7.82)
Based on the results, the data supports the hypothesis because the allele frequencies in the bean population change over generations. Figure 3 and 4 show that the allele frequencies of the 10th generation is different than the 1st generation for both populations. Chi-square is greater than the critical value for degrees of freedom of 3 (Population A: 27.16>7.82, and Population B: 142.5>7.82), meaning there is a significant change in alleles in both population A and B.
Natural selection is the evolutionary process demonstrated in this exercise instead of the genetic drift. As shown in figure 5, the red and speckled beans are relatively larger in size compared to black and white beans. Their larger size contributed to higher chance on being selected to survive to the next generation because they are the easiest to pick. The number of white and black beans decrease significantly in both populations due to their smaller size that makes them sink to the bottom of the gene pool, thus results in fewer chances to be picked. Genetic drift occurs by chance, and it is not related to the fitness of alleles. Therefore, we reject the null hypothesis because natural selection is occurring in the population, which makes the allele frequencies change over generations. The allele frequencies of the 10th generation differ so greatly from the 1st generation that it is very unlikely to have occurred by chance alone.
Hey great post guys! I just commented on another post and they also had the same chi squared value for part A, 0.08. I think that's really cool that two separate groups can have the same value. Also, I find it very interesting that in part B, both of your populations had similar results. In both, the black and white beans either were eliminated or got very close, while the speckled and red beans increased in frequency. In my lab group, we did not see any elimination of alleles. It's interesting how two groups can also have very different results! Anyways, good graphs and I like the addition of pictures.
ReplyDeleteI love that you included photos of the bean pairs laid out together, not only is it direct proof that your data is correct & honest, but its a different & cool way to show your data rather than just a bar graph or table! I find it surprising that so many of us got the same results for the first experiment. I expected there to be a greater variety in our results, but I think that may happen with larger sample groups and more repetitions of the experiment. I think your graphs and tables are easy to read and your writing is clear and to the point! Good job.
ReplyDeleteYou mentioned that the larger size of the red and speckled beans gave them an advantage in remaining in the gene pool from generation to generation, and the fact that both of those bean types neared fixation as the other beans were lost or nearly lost in both independent trials seems to support that conclusion. I am curious as to what method you used to divide your population in each generation. Perhaps if you had used a different selection method, one which eliminated the influence of size, your results would have been more consistent with genetic drift than natural selection.
ReplyDeleteThank you so much for making the font easy to read and the layout of your post is fantastic. The bar graphs and the captions are clear and concise. I was surprised that you got so many heterozygous beans in part one of the experiment and so low homozygous. I would of liked to see more data for the generations, but overall great post.
ReplyDeleteGreat work overall; you explained your process and calculations clearly and included the appropriate amount of images. I love the bright colors and distinct shapes in your graphs, but they would be easier to compare if they had the same key; that difference threw me off.
ReplyDelete